Termination w.r.t. Q of the following Term Rewriting System could not be shown:
Q restricted rewrite system:
The TRS R consists of the following rules:
f3(0, 1, X) -> h2(X, X)
h2(0, X) -> f3(0, X, X)
g2(X, Y) -> X
g2(X, Y) -> Y
Q is empty.
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
f3(0, 1, X) -> h2(X, X)
h2(0, X) -> f3(0, X, X)
g2(X, Y) -> X
g2(X, Y) -> Y
Q is empty.
Q DP problem:
The TRS P consists of the following rules:
F3(0, 1, X) -> H2(X, X)
H2(0, X) -> F3(0, X, X)
The TRS R consists of the following rules:
f3(0, 1, X) -> h2(X, X)
h2(0, X) -> f3(0, X, X)
g2(X, Y) -> X
g2(X, Y) -> Y
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ DependencyPairsProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
F3(0, 1, X) -> H2(X, X)
H2(0, X) -> F3(0, X, X)
The TRS R consists of the following rules:
f3(0, 1, X) -> h2(X, X)
h2(0, X) -> f3(0, X, X)
g2(X, Y) -> X
g2(X, Y) -> Y
Q is empty.
We have to consider all minimal (P,Q,R)-chains.